This is a homework problem I have. I don't remember learning the difference, and searching hasn't helped explain the difference between the capitalization.
4 Answers
We may symbolically write:
- $\arcsin\ $ = $\sin^{-1}\, $
- Arc$\sin\ $ = Sin$^{-1}\, $
because
- $\arcsin\ $ and $\sin^{-1}\, $ are only two different notations for the same function,
- Arc$\sin\ $ and Sin$^{-1}\, $are only two different notations for the same maping.
Definition: The Arcsine of $x$, denoted $\operatorname{Arcsin}(x)$, is defined as "the set of all angles whose sine is $x$". It may be interpreted as a one-to-many relation.
Definition: The arcsine of x, denoted $\arcsin(x)$, is defined as “the (only) angle from the closed interval $[-\pi/2, +\pi/2]$ whose sine is $x$”. It may be interpreted as a one-to-one relation.
So, for example
$$\arcsin\left(\frac1 2\right)= \sin^{-1}\left(\frac1 2\right) = \frac{\pi}{6} $$
while
$$\operatorname{Arcsin}\left(\frac1 2\right)= \operatorname{Sin^{-1}}\left(\frac1 2\right) = \left.\left\{\frac{\pi}{6} + 2k\pi, \frac{5\pi}{6} + 2k\pi\ \right| \ k \in \mathbb Z\right\} $$
See also definitions and illustrations of these functions / mappings in The Algebra Help e-book on MathOnWeb.com site.
Edit:
It seems that definitions for capitalized and lowercase names are swapped. Several other sources — see the jgon's answer — defines them in the opposite manner.
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While I'm almost certain the other answers are correct about $\arcsin$ being equivalent to $\sin^{-1}$, the majority of sources I can find contradict the answers given by MarianD and Polygon:
- The Math Forum's "Ask Dr. Math": Inverses of Trigonometric Functions
- MathWords.com: Inverse Trigonometry
- Dummies.com: How to distinguish between trigonometry functions and relations
- MathWorld: Inverse Trigonometric Functions
- SparkNotes: Inverse Trigonometric Functions
According to these sources $$\arcsin x =\sin^{-1}(x) = \{ \theta \in\Bbb{R} : \sin \theta = x\} ,$$ whereas $$\operatorname{Arcsin} x =\operatorname{Sin}^{-1}(x)= \theta,$$ where $\theta$ is the unique angle between $-\pi/2$ and $\pi/2$ (inclusive) such that $\sin\theta = x$, which is often called the principal value.
Side note
I'd like to comment that in practice, in most cases the lower case variants are used to denote the principal value, and the upper case variants are not used at all. However, when they are used, this does appear to be the correct answer regarding their meaning.
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MathOnWeb.com is an example of a source, which strictly contradict your answer. – MarianD Mar 16 '19 at 05:59
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1@MarianD I've retracted my downvote on your answer in light of the new source, but imo the majority of sources appear to support my answer, including ones I have high confidence in, like Wolfram MathWorld. – jgon Mar 16 '19 at 18:32
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Sin$^{-1}$ (with a capital S) returns every value you could put into the sine function to get your input. So $\operatorname{Sin}^{-1}(\sqrt2/2) = \{\cdots\frac{-7\pi}4,\frac{-5\pi}4,\frac\pi4,\frac{3\pi}4,\frac{9\pi}4,\frac{11\pi}4\cdots\}$.
But with a lowercase s, it only returns values between $\frac{-\pi}2$ and $\frac\pi2$.
So $\sin^{-1}(\frac{\sqrt{2}}2)$ is just $\frac\pi4$.
The notation with the capital S is rarely used because it is not a function; one input gives you infinitely many outputs.
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Is it then possible to give a statement right at the beginning, for eg, consider the domain ___< x < _____, then we use capital S, for inverse sine, such that we only have limited answers within { } instead of infinite answers? – NetUser5y62 Jul 01 '16 at 15:12
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It says on my sheet that Arcsin refers to 2 quadrants while arcsin refers to 4 quadrants. Is it the reverse for $\sin^{-1}?$ – Jack Pan Jul 05 '16 at 20:29
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That is a strange way of describing arcsin vs Arcsin, but it is true. If you look at the graph of arcsin(x), you will see that it is only in quadrants I and III, but Arcsin(x) is in all four. It is the same for $\sin^{-1}$. – Polygon Jul 06 '16 at 00:14
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(-1) I can find no sources supporting this answer, see the sources linked in my answer. – jgon Mar 16 '19 at 04:57
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@jgon It looks like you're right. My answer was based off what I had learned in my high school math course, but it looks like I had written it down wrong. I just found two sources supporting what you said. – Polygon Mar 16 '19 at 05:02
$\operatorname{Arcsin}$ is used when showing $\sin^{-1}x$ as a relation whereas $\arcsin$ is used when showing $\sin^{-1}x$ as a function. If you put the function sin^-1(x) into Desmos or a graphing calculator set to radians, you can see the graph of the arcsine function (inverse function of $\sin x$). You will also see that the line stops abruptly at $x=-1$ and $x=1$ and $y=-\pi/2$ and $y=\pi/2$. Since there cannot be two $y$ values for any one $x$ value, the graph stops. We denote this segment as the "arcsine". But if the graph continued as a relation, it would look like a sine function stretching from $y=-\infty$ to $y=\infty$. We denote this as "Arcsine".
I hope someone finds this useful.
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1Welcome to MSE. For some basic information about writing mathematics at this site see, e.g., basic help on mathjax notation, mathjax tutorial and quick reference, main meta site math tutorial and equation editing how-to. – José Carlos Santos Apr 30 '21 at 03:43
In the older days with typewritters, people could not type $sin^{-1}(x)$ on a type writter. So they used $arcsin(x)$ instead.
– Jul 01 '16 at 14:47