I am studying for a teacher exam and I am stumped with this problem $3\cdot \frac{(2+6)^2}{6}$
I know that the answer is $32$ because of the answer sheet, but how and why is this the answer? Can I get an example?
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1Where did you stuck ? Are you able to calculate $(2+6)^2$ ? – callculus42 Jul 02 '16 at 14:25
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no I can not remember how to calculate this? its been awhile for me – tina Jul 02 '16 at 14:30
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OK, what is $2+6$ ? – callculus42 Jul 02 '16 at 14:31
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Start by calculating $2+6$. – Jul 02 '16 at 14:34
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Hi I got the equation. I was squaring 8 instead of 7. It seems Like I had a brain fart. 2+6 is 7^2 is 49*3=147/6=32 – tina Jul 02 '16 at 14:36
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No. $147/6=24.5$ – Jul 02 '16 at 14:43
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2+6 is 7^2=49*3=147/6=32. Do what's in parenthesis first – tina Jul 02 '16 at 14:46
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$6+2$ is not $7$. – Jul 02 '16 at 14:47
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sorry a typo 2+6 is 8 and 8 squared is 64. 64*3 is 192 and 192/6 is 32 – tina Jul 02 '16 at 14:52
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1Yes. But it might be easiert to first calculate the fraction of 3 and 6: $\frac{3}{6}$. Then take the intermediate result of 64 and multiply it by $\frac{3}{6}=\frac{1}{2}$: $ \ \ $ $64\cdot \frac12=64/2=32$ – callculus42 Jul 02 '16 at 14:56
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It seems that you did find your way to the correct answer, so just to summarize one correct sequence of steps you could take to get there, we have (using the method that callculus described in a comment): $$3\cdot\frac{(2+6)^2}{6}=3\cdot\frac{8^2}{6}=3\cdot\frac{64}{6}=\frac{3}{6}\cdot64=\frac{1}{2}\cdot64=32$$
Robert Howard
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