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I know how to solve equations with absolute values but without a parameter in the absolute value.

If "a" is a real and positive parameter

|2x - 3a| + |a + 1 - x| = |x + 1|

But how can to approach this equation. I would be thankful for some tips and advice.

Gigaxel
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    Well, just consider cases $$x\ge / < \frac32a \ x\le/>a+1 \ x\ge/<-1$$ –  Jul 06 '16 at 07:08
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    Afterwards, you'll need to check for what values of $a$ the solutions you get agree with those conditions (which might contain a check of their consistency as well). –  Jul 06 '16 at 07:11
  • @G.Sassatelli Thank you. I was thinking something like that, but I was not sure cause I've never encountered an equation like this. Now it makes all perfect sense to me. Thank you very much :D – Gigaxel Jul 06 '16 at 07:21

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