Let $m,a,l,b \in \mathbb{Z}^{+}$
How can I prove $\frac{m+a}{m+a+l+b}$ is between $\frac{m}{m+l}$ and $\frac{a}{a+b}$?
Let $m,a,l,b \in \mathbb{Z}^{+}$
How can I prove $\frac{m+a}{m+a+l+b}$ is between $\frac{m}{m+l}$ and $\frac{a}{a+b}$?
Hint: $$ \frac{a+c}{b+d}-\frac ab=\frac{bc-ad}{b(b+d)} $$ and $$ \frac{a+c}{b+d}-\frac cd=\frac{ad-bc}{d(b+d)} $$