I have a function f(x,y) which is 1 at the origin and 0 for any other point. This function isn't continuous because the limit doesn't exist at (0,0). Could you show its partial derivatives exist. (not homework)
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You might want to try f =0 on the axes and f = 1 everywhere else. – zhw. Jul 29 '16 at 23:49
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For example:
$$\frac{\partial f}{\partial x}(0,0):=\lim_{x\to0}\frac{f(x,0)-f(0,0)}x=\lim_{x\to0}\frac{0-1}x$$
so nop: the partial derivatives don't exist at the origin. They do at any other point, though.
DonAntonio
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