If this is what you mean by the description of your graphs...
say slops are $ma, mb $ and $ mc$ for above graphs.
Then your intuition is quite clear, with an assumption that slop for graph b, $ mb < 1$ (very small, as you wrote), in that case
Now consider 2 points on each of these graphs, $ p1, p2, q1, q2$ and $r1, r2$, of form $(tm1, out1), (tm2, out2), (np1, out1), (np2, out2), (am1, out1), (am2, out2)$ respectively.
so having first two graphs How can you construct the third one:
Clearly if $Avg. Money = {Total Money\over No. Of people}$,
each corresponding point for out1, out2 can be calculated directly by
Dividing corresponding y-coordinate of graph 1 to that of graph 2.
Now when considering the slops,
see the change you did in np1 and np2 will be very less(as the slop is very less, considering it's <1) while tm1 and tm2 will be large.
it follows
$\vert{{{tm2 - tm1 \over (\Delta outcome)} \over (np2-np1) }}\vert > \vert{tm2 - tm1 \over (\Delta outcome)} \vert$
Or you can directly infer that you are Dividing a Negative number with a positive number which is less than 1.
So magnitude would increase. But sign will remain same (negative).
Note: The linearity of graphs above can be replaced with curves as long as the slop constraints you wrote, are not violated.