I'm confused b/w the structure of standard topology on $\mathbb R $ i.e,$\mathbb R $ & the structure of K-topology on $\mathbb R $ i.e,$\mathbb R_K $
Since, standard topology on $\mathbb R$ is generated by (a,b),whereas the K-topology on $\mathbb R$ $(a,b)\cup(a,b)-$K.
But,$(a,b)\cup(a,b)-$K=$(a,b)$.
Therefore,standard topology on $ \mathbb R$ and $\mathbb R_K$ are generated by the collection of open intervals on the real line.Hence,Standard topology on $\mathbb R$=$\mathbb R_K$.
But,this result is wrong,as $\mathbb R_K$ is strictly finer than the Standard topology on $\mathbb R$ .
NOTE
$K-$topology on $\mathbb R$==let $K$ denote the set of all numbers of the form $1/n$,for $n \in \mathbb Z_+$,and let β′′ be the collection of all open intervals (a,b),along with all sets of the form (a,b)−K.The topology generated by β′′ will be called K−topology on R
Standard topology on $\mathbb R$==let β be the collection of open intervals in the real line,$(a,b)={x:a<x<b}$, the topology generated by β is called the standard topology on $\mathbb R$.
Help me in clearing this concept,i've just started studying topology.