I have graphed this equation $y = x^2$ and I got this output:
Is it correct?
On the other hand, this I what I got in Wolfram|Alpha:
How do I can analog/compare these two graphs in such a way I can deduce one from the other?
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1Seems to be $z = x^2$ in WolframAlpha ($(0,1,0)$ belongs to the graph). – Abstraction Aug 12 '16 at 15:35
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You should provide your WA input as part of your question. – user21820 Aug 12 '16 at 15:37
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As @Abstraction said, the second plot is $z=x^2$, because it does not depend on $y$. – InsideOut Aug 12 '16 at 15:41
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You can always force certain output in WA by specifying the dependent variable, try $y(x,z)=x^2$ and it will return the graph with z instead of y – Triatticus Aug 12 '16 at 17:12
2 Answers
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Your plot is correct, and I am not sure why Wolfram Alpha is mislabeling axes. You can notice it is really the same graph, just the $y$ and $z$ axes are flipped.
gt6989b
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This is why one should know how to evaluate veracity of software outputs! – user21820 Aug 12 '16 at 15:36
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That is correct, as you say, you sketch a parabola in $xy$ plane and then imagine an infinite amount of those parabolas pallarel to each other, on planes that range on different height lines $z\in(-\infty,\infty)$ .
note that I believe wolfram had mixed the z and y lines.
Anyhow you can align the axis in any way you desire as long as all 3 lines are perpetual.
oBit91
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