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I asked this question long time ago; however, I forgot to ask how would the graph of the derivative, and the original expression $x^i$ look like. $i$ is the imaginary unit for which $i^2=-1$

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Sigma6RPU
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  • It is not a function whose values are real. Only the domain is in the reals. – Crostul Aug 16 '16 at 17:21
  • @Crostul So could I just graph it in the complex plane? But I don't know how to necessarily evaluate a real number $a$ to the power of $i$. – Sigma6RPU Aug 16 '16 at 17:24
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    In the previous question it is defined $x^i=e^{i \log x} = \cos \log x + i \sin \log x$. Now, plotting the graph gives you the unit circle. – Crostul Aug 16 '16 at 17:31
  • @Crostul Ohhhhhhhhh. Ok that actually made life easier. thanks – Sigma6RPU Aug 16 '16 at 17:32

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