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A portion of a sketch drawn by a student to obtain the location of a point P which lies at a distance of 3cm from the given straight line AB and 5cm from the point A, is shown in the figure. Complete the sketch and mark the location of the point P.

enter image description here

Any ideas on how to begin?

user360471
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    Put point $P'$ with a distance 4cm from $A$, then draw a perpendicular line to $AB$ at $P'$ then the intersection of the perpendicular line and $CD$ is your point $P$ – iamvegan Aug 21 '16 at 09:36
  • It's the same point where AB is 4 cm the line CD is 4cm .Is that point P? and why chose 4cm away from AB instead of 5 which the question mentions – user360471 Aug 21 '16 at 09:47
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    $|AP'|=4$ implies $|AP|=5$ – iamvegan Aug 21 '16 at 10:01
  • using set notation i guess? and why use " ' " the dash of the lines – user360471 Aug 21 '16 at 10:04
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    By Pythagoras Theorem $|AP'|^2+|PP'|^2 = |PP'|^2$ since $|AP'|=4$ and $|PP'|=3$ we have $|AP|=5$ – iamvegan Aug 21 '16 at 10:07
  • If a compass is allowed then draw circle centered at A with radius 5 cm. Intersection of this circle and your line CD is point P. – tighten Jun 11 '17 at 21:23

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