Solving for a variable using a logarithm with a base not 10?

Question

So I have this expression: $C=Ba^{(t/D)}-k$ and I'm asked to solve for $t$ using a logarithm with base a $log_{a}$. So far, I've gotten ${((C+k)/B)} = a^{(t/D)}$. How do I move forward?

Note that $\log_a (a^x) = x$. So taking $\log_a$ of both sides will help. — ItsNotMeItsYou, Aug 24 '16 at 05:17

score 0 · Answer 1 · answered Aug 24 '16 at 05:17

0

$$\log_aa=1$$ $$C +k=Ba^{(t/D)}$$ $$\log_a(C +k)=\log_aB +\log_aa^{(t/D)}$$

answered Aug 24 '16 at 05:17

Aakash Kumar

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Solving for a variable using a logarithm with a base not 10?

1 Answers1