If f(x)=x^2+1, then (f o f)(x)=?
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$\begin{array}{ccc} (f\circ f)(x) = f(f(x)) &=& (f(x))^2 + 1 \\ &=& (x^2 +1)^2 +1 \\ &=& x^4 + 2x^2 + 1 + 1 \\ &=& x^4 + 2x^2 + 2 \end{array}$
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