2

I can find a discontinuous function having the above conditions..... f(x) =x for x lying betwen (0,1) and (1,2) and -10 at x=1 But can anyone help me in finding a continuous function satisfying the conditions....

1 Answers1

3

I think you can consider the function $$y=\bigg\{ \begin{array}{ccc} x^2 \sin^2\frac{1}{x}& &x\ne0 \\0 && x=0\end{array}$$ It is continuous and $(0,0)$ is a local minimum, but does not satisfy your conditions.

velut luna
  • 9,961
  • I still have a doubt...f(x) at 0.1 and - 0.1 are equal......i.e. it is decreasing in left interval and increasing in right..... – user364168 Aug 29 '16 at 14:40
  • @user364168 the values at some arbitrarily chosen points $\pm 0,1$ are of no relevance in case of a highly oscillating map like the one proposed here. – Thomas Aug 29 '16 at 15:07
  • Okay.....i understood....thank u all...... – user364168 Aug 29 '16 at 15:26