I can find a discontinuous function having the above conditions.....
f(x) =x for x lying betwen (0,1) and (1,2)
and
-10 at x=1
But can anyone help me in finding a continuous function satisfying the conditions....
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user364168
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2What about $y=x^2\sin^2\frac{1}{x}$ for $x\ne 0$ and $y=0$ for $x=0$? – velut luna Aug 29 '16 at 13:57
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I think you can consider the function $$y=\bigg\{ \begin{array}{ccc} x^2 \sin^2\frac{1}{x}& &x\ne0 \\0 && x=0\end{array}$$ It is continuous and $(0,0)$ is a local minimum, but does not satisfy your conditions.
velut luna
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I still have a doubt...f(x) at 0.1 and - 0.1 are equal......i.e. it is decreasing in left interval and increasing in right..... – user364168 Aug 29 '16 at 14:40
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@user364168 the values at some arbitrarily chosen points $\pm 0,1$ are of no relevance in case of a highly oscillating map like the one proposed here. – Thomas Aug 29 '16 at 15:07
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