I was procrastinating here (:O) and found this question I liked -
If you start with $\{3,4,12\}$, and at each step replace any two numbers $a,b$ in the set by $\frac{3a}{5}+\frac{4b}{5}$ and $\frac{4a}{5}-\frac{3b}{5}$, can you reach $\{4,6,12\}$ in finite time? Answer:
No, because the operation described above leaves the sum of the squares of the set constant, which differ between the two sets described.
So, does anyone know of any other interesting questions involving invariants, either from this site or elsewhere?