$$\log(5x + 5) = 2\log(x + 1)$$
Thats the original question. So far I have gotten.
$$\log(5x + 5) = \log(x + 1)^2$$
I am not looking for the answer maybe just a hint in the right direction.
Thanks!
Asked
Active
Viewed 22 times
0
-
Hint: since you have $\log$ on both sides of the equation, take the inverse function of it. – Edu Oct 13 '16 at 10:44
-
So can I drop the log from both sides? ie 5x + 5 = (x + 1)^2 – John Allen Oct 13 '16 at 11:12
1 Answers
2
Hint:
A logarithm is an injective function, which means that if $\log(a)=\log(b)$, then $a=b$.
Just be careful, that $\log(a)=\log(b)$ also implicitly means that $a,b>0$.
5xum
- 123,496
- 6
- 128
- 204
-
So would I be correct in saying I can drop the logs from both sides? – John Allen Oct 13 '16 at 11:10
-
@JohnAllen Yes, as long as you are careful not to get any negative solutions. – 5xum Oct 13 '16 at 11:13
-
Thanks for the warning about the negative solutions that would definately have caught me – John Allen Oct 13 '16 at 11:48
-