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I've been pretty stuck on trying to show how a conjugation is a group action:

A group $G$ acts on itself via conjugation, where $\phi_g(x)$ = $gxg^{-1}$. Prove that conjugation is a group action.

How do I show that conjugation is a group action? Thank you.

Max
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1 Answers1

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You have to check two things.

  • If you denote $e$ the neutral element of $G$, for all $x\in G$ you have

$$\phi_e(x)=exe^{-1}=x.$$

  • And if $g,h\in G$, for all $x\in G$ you have

$$\phi_g(\phi_h(x))=\phi_g(hxh^{-1})=g(hxh^{-1})g^{-1}=(gh)x(gh)^{-1}=\phi_{gh}(x).$$

Then you have proven that it is a group action.

user26857
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E. Joseph
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  • I should have specified the 2nd part was what I was having trouble with. Thank you so much, I understand it now. – Max Oct 16 '16 at 07:50