While trying to parametrise the intersection between $x^2+y^2=z^2$ and $z=\frac x2+2$, polar coordinates gave me $$r^2=4+2r\cos t+\frac14(r\cos t)^2$$ which returned two values of $r$: $$r=-\frac4{\cos t\pm2}$$ Using the form $\{r\cos t,r\sin t,\frac{r\cos t}2+2\}$, I was able to plot the intersecting shape. However I am still confused why both values of $r$ work and produce the same shape.
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Aww, I had to put in MathJax for you... – Parcly Taxel Oct 23 '16 at 05:54