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$n\cdot2^n = r,\; r \in \mathbb{Q}, n \in \mathbb{R}$

I'm trying to solve for the input size of a $n\cdot \log_2 n$ algorithm, i.e. I started out with $n\cdot \log_2 n = 100$

Akay
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1 Answers1

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$$n = \dfrac{W(r \ln(2))}{\ln(2)}$$ where $W$ is the Lambert W function

Robert Israel
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