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Given $A=(x\in \Bbb R :x>0)$, we define $xRy \iff y/2 \leq x \leq 2y.$

Okay, there isn't any $x$ that satisfy this, but which equivalence relation is this? I think it's symmetric, but how do I prove it?

Rodrigo Dias
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George S
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1 Answers1

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$xRy \implies y/2 \leq x \leq 2y \implies y/2 \leq x$ and $ x \leq 2y $ which can then be algebraically manipulated into $y \leq 2x$ and $ x/2 \leq y $. Recombining $ x/2 \leq y \leq 2x \implies yRx$