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Question

which one will be larger,

$99^{99}-99^{98}$

or

$99^{98}$

I could not find any exponent properties that will help solving this.

$99^{98}(99-1) = 99^{98}\cdot 98$ clearly the first one. done — Anonymous, Oct 30 '16 at 17:00

score 4 · Answer 1 · answered Oct 30 '16 at 15:56

4

You could use substitution. Let $99^{98}$ be $x$. Then the two choices would be $$99x-x$$ and $$x$$ Now you can obviously see that $99^{99}-99^{98}$ is larger.

answered Oct 30 '16 at 15:56

suomynonA

6,895

That explains it. Thanks. – user3188039 Oct 30 '16 at 16:18

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