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For a differentiable continuous function $g(u)$ over a finite region $R$, I know that $$\int_R e^u g\; u\; du = 1$$ Is there any way to determine from this the value of $$\int_R 10^u g\; u\; du$$

Oliver
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2 Answers2

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The second integral is

$$J=\int 10^u g(u)du =$$

$$=\int e^{uln(10)}g(u)du=.$$

put $v=u ln(10)$

then

$$J=\frac{1}{ln(10)}\int e^v g(\frac{v}{ln(10)})dv.$$

So, in general, we cannot get tha value of $J$

from $I=\int e^u g(u)du=1$.

if $g$ is linear then $J=\frac{1}{(ln(10))^2}$.

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No, it depends on $g$ look at the two cases $g(x)=x$ and $g(x)=x^2$.

  • How do I look at these? What is known is the value of the integral. The function g is identical for the two integrals shown; the only difference is $e^u$ vs $10^u$. – Oliver Nov 02 '16 at 08:49