It's pretty obvious why it doesn't work using the sequence algorithms.
So the way I thought of it:(n is the number of vertices)
at n = 1: you get 0, which is the graph of just one vertex
at n =2: you get 1, 0 which is two vertices with one having a degree of 1, but the other vertex has no edges so this is impossible.
this continues on for n greater than 2 as well. Not sure if this is enough to answer the question.
Edit: possible new solution, there are n possible degrees for n vertices which is impossible when $n\geq2$