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Does the series $\sum_{n=1}^\infty \frac{\ln n}{n}$ converge?

Is there a way to determine this besides a comparison test?

Romeo
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Sithe
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  • You can use the integral test if you don't like the comparison test –  Nov 12 '16 at 19:40

1 Answers1

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Hint. The given series is divergent

  • by comparison with the harmonic series: $$ \frac1n<\frac{\log n}n , \qquad n \geq 3, $$
  • by the integral test: $$ \frac{\log^2 N}2=\int_1^N \frac{\log x}x\,dx\le\sum_{n=1}^N\frac{\log n}n $$ letting $N \to \infty$.
Olivier Oloa
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