Write down an example of a sequence ${a_n}$ such that:
${a_n}$ is divergent
$a_n < 5$ for all $n$, and
$a_n < a_{n+1}$ for all $n$,
or explain why no such divergent sequence exists.
What I did thus far:
We know that the sequence is increasing since we are given that $a_n < a_{n+1}$ for all $n$, thus we can also say that it is monotonic.
We also know that the sequence is bounded from above since we are given that $a_n < 5$ for all $n$.
By the Monotonic Sequence Theorem, we know that every bounded and monotonic sequence is convergent.
Thus, no such divergent sequence exists.