A frog hops and lands exactly 1 meter away at a time..

Question

I am stuck with the following problem:

A frog hops and lands exactly 1 meter away at a time . What is the least number of hops required to reach a point 10 cm away ?

The options are:

1.$\,\,1$

2.$\,\,2$

3.$\,\,3$

4.It can't travel such a distance.

The answer is given to be 2. But I have no clue how to tackle it. Can someone explain. Thanks in advance for your time.

Well, nobody said the frog has to jump in one dimension (only left/right) — Troy, Nov 19 '16 at 06:39
The question was taken from a competitive exam papers and it carries only 2 marks. — learner, Nov 19 '16 at 06:40
I just understood, oh, we are on a plane, it's not that you have two directions to hop! So then you can just create a triangle with sides $1,1,0.1$ and hop along. This is a tricky question — Sarvesh Ravichandran Iyer, Nov 19 '16 at 06:40

vidyarthi · Accepted Answer · 2016-11-19T06:46:36.763

3

The answer is $2$. This is straightforward, as pointed out in the comment. Since a triangle can be constructed with sides $1m, 1m, $ and $10 cm$; therefore first the frog, say from point A jumps to point B $1m$ apart. Then, the frog jumps to anither point C $1m$ apart but just $10cm $ away from point A thus total displacement being $10 cm$.

edited Nov 19 '16 at 06:46

answered Nov 19 '16 at 06:43

vidyarthi

7,028

thanks a lot.It makes sense. Got your point. – learner Nov 19 '16 at 06:44

A frog hops and lands exactly 1 meter away at a time..

1 Answers1