I am facing issue solving below problem. Any help?
Total number of tasks are 6780 in a year. And 17 people are efficiently working in a year to complete different tasks to 100%.
Now there will be 20% work increase next year.
How many more people we require to handle that 20% extra load efficiently?
Work and manpower are in direct proportion (at least this is the ideal case for your problem). So if you have a 20% increase in the work, then you should have a 20%=3.4 people increase in the manpower too in order to complete the work in the same time. This is regardless of the number of tasks.
Without loss of generality assume that the workload of the current year corresponds to 100 units (of tasks if you will). Each person can therefore handle $100/17$ units of workload. Next year there will be 120 units, and we know that $x$ people can handle $x\times(100/17)$ units. Thus the solution to how many people we need (in total) for next years 120 units of workload is the solution of: $x\times(100/17)=120$, with respect to $x$.
