The Lagrangian is given by
$$L = x(y+4) + \lambda [8-x-y] $$
F.O.C. are given by
$$ y+4-\lambda=0 \\
x-\lambda=0 $$
Finally, we know that
$$ x+y=8 $$
Solving this system we find that $x=6$, $y=2$ and $\lambda=6$ as you correctly found. The value of Z at the point $(x,y)=(6,2)$ is 36.
That Lagrange multiplier is positive means that relaxing constraints will lead to an increase in the value of Z. In other words, imagine that the constraint was $x+y=a$ for some $a>0$. Then if you find that at a given value of $a$, in your case $a=8$, $\lambda>0$ then it means that increasing $a$ would lead to a new solution at which the value of Z will be higher than before.
Note: It is a little bit strange to talk about relaxing the constraints in the case of equality constraints. Typically, such language makes sense if the constraint is written as inequality, for example in your case as $x+y \leq 8$.