I'm wondering whether $((A\to B)\land (\lnot A \to C)) \iff (A\lor C)$ is correct or not.
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10Have you tried using a truth-table? If not, what else have you tried? – amWhy Jan 08 '17 at 23:29
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Do you mean B or C (not A or C)? – user404127 Jan 08 '17 at 23:41
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1Since $(\lnot A \to C) \equiv (A\lor C)$, we have $((A\to B) \land (\lnot A \to C)) \rightarrow (A\lor C))$, But not vice-versa. So the biconditional is wrong. – amWhy Jan 08 '17 at 23:45