It is given , that AB=AC=AG. Now,if we draw a circle with centre A and AB as radius then,how should we prove that the circle will also pass through the points C and G?
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1Isn't the circle the set of all points at a given distance from its center? – AdLibitum Jan 09 '17 at 19:01
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What is the definition of circle in your geometry book?
It is going to be something like, "A circle is the set of all points a given distance from the center."
C,G are the given distance from the circle. They lie on circle A by definition.
Doug M
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The equation of the circle with center$(a, b)$ and radius $r$ is $(x-a)^2+(y-b)^2 = r^2$.
If this equation is satisfied by points A and B, then points A and C also satisfy this since the distances are the same; similarly for A and G.
marty cohen
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