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enter image description here Only a part is needed. Thanks.

George Law
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1 Answers1

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Some trigonometry is required, but the gist of it is that because the particle is at rest (not accelerating) the horizontal component of the tension in $BP$ is equal to the horizontal component of the tension in $AP$. All you have to do is figuring out all the angles involved and decompose all the forces correctly.

Arthur
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