enter image description here Only a part is needed. Thanks.
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Ouch, my neck. Couldn't you have rotated that image before you uploaded it? – Arthur Jan 23 '17 at 13:48
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Some trigonometry is required, but the gist of it is that because the particle is at rest (not accelerating) the horizontal component of the tension in $BP$ is equal to the horizontal component of the tension in $AP$. All you have to do is figuring out all the angles involved and decompose all the forces correctly.
Arthur
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