¿Do you know if there is any mathematical theory (or axiomatic theory) whose axioms, or at least one of them, contradict with other axioms of another theory?
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1Do you mean like whether you assume the axiom of choice or not? – Michael Burr Feb 01 '17 at 23:36
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No, because, if I am not mistaken, the axiom of choice is not contradicted by any other axiom of any other theory. – Eduardo Feb 02 '17 at 08:22
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1https://en.m.wikipedia.org/wiki/Non-Euclidean_geometry – Peter Szilas Jun 14 '17 at 12:56