I am not getting any idea . Can anybody provide me a hint
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HINT:
$$x^2+y^2+8x+8y+16+\lambda(x+y+12)=0$$ represents the equation of the circle passing through the intersections$A,B$ of $$x+y+12=0$$ and $$x^2+y^2+8x+8y+16=0$$
lab bhattacharjee
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Now finding the points is getting very complicated – a25bedc5-3d09-41b8-82fb-ea6c353d75ae Feb 19 '17 at 13:23
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For the circle $$(x+4)^2+(y+4)^2=4^2,$$ any point can be written as $$(-4+4\cos t,-4+4\sin t)$$ can you find the two values of $t?$ – lab bhattacharjee Feb 19 '17 at 13:25
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I got t=$\pi $ and $3\pi/2$ . Now how to find the equation of circle – a25bedc5-3d09-41b8-82fb-ea6c353d75ae Feb 19 '17 at 13:28
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@user123733, Now when $y=mx$ be a tangent of $$x^2+y^2+8x+8y+16+\lambda(x+y+12)=0?$$ – lab bhattacharjee Feb 19 '17 at 13:31