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How to solve this exponential equation $$2^{2x^2} + 2^{x^2+2x+2}= 2^{5+4x}$$

Levi
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1 Answers1

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HINT:

$$(2{x^2})^2+2^{x^2}\cdot2^{2x+2}-2\cdot(2^{2x+2})^2=0$$

$$\iff\left(2^{x^2-2x-2}\right)^2+2^{x^2-2x-2}-2=0$$