How to solve this exponential equation $$2^{2x^2} + 2^{x^2+2x+2}= 2^{5+4x}$$
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HINT:
$$(2{x^2})^2+2^{x^2}\cdot2^{2x+2}-2\cdot(2^{2x+2})^2=0$$
$$\iff\left(2^{x^2-2x-2}\right)^2+2^{x^2-2x-2}-2=0$$
lab bhattacharjee
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See http://math.stackexchange.com/questions/384090/find-all-real-numbers-x-for-which-frac8x27x12x18x-frac76 – lab bhattacharjee Mar 01 '17 at 14:04