Let the equation be $f (a,b)=\int_\Omega g(a,x)g(b,x)dx $
If the condition on f is : $f (a,b)=h (a-b) $ can we prove that $g (a,x) $ is of the form $k (a-x) $ ?
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Is the RHS a definite integral? If so, what are the upper and lower bounds? – kennytm Mar 08 '17 at 13:09
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Yes it's a definite integral. I forgot to add that h is $2\pi $-periodical. – QuantumPotatoïd Apr 20 '17 at 09:00