How can I solve this? I've tried many ways, but it's all useless. Need help!
$$\int\frac{\mathrm dx}{a^2\sin^2x-b^2\cos^2x}$$
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i would use the Weierstrass substitution – Dr. Sonnhard Graubner Mar 15 '17 at 16:53
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$\int{\sec^{2}\left(x\right) \over a^{2}\tan^{2}\left(x\right) - b^{2}},\mathrm{d}x$ – Felix Marin Mar 19 '17 at 00:19
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HINT:
Divide numerator & denominator by $\cos^2x$
Set $\tan x=u$
OR
Divide numerator & denominator by $\sin^2x$
Set $\cot x=v$
lab bhattacharjee
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