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I need to make an infinite sequence of natural numbers which contains no prime numbers, yet any pair of them are co-prime with each other. I tried just finding numbers between 1 - 100 that forms a co-prime list, but couldn't find a pattern or rule that justifies it.

2 Answers2

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You could try:

$$\{p^2|p \in primes\}$$

JMP
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let $a_n$ be a sequence of natural number such that :

$a_n = p_{2n} p_{2n-1}$ where $p_n$ is the $n$-th prime number surely that $a_n$ contain no prime and every element in the sequence will be co-prime to all other elements in the sequence and there will be infinitely many(Euclid proof).

the sequence starts with $\{6,35,143,323,667,1147,1763,2491,3599,\cdots \}$

Ahmad
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