How do I solve $n <8 \log_2(n)$?

Asked Apr 03 '17 at 15:16

Active Apr 03 '17 at 15:27

Viewed 57 times

I am several years away from college so I've forgotten my math and I don't know how to solve this one. I've reviewed several logarithmic properties but I'm still stumped.

I am at this part:

move 8 to other side of equation: $$\log_2 n < n/8$$

convert to exponential form: $$2^{n/8} < n$$

Now what? anyone?

edited Apr 03 '17 at 15:27

asked Apr 03 '17 at 15:16

user6388032

https://math.stackexchange.com/questions/20652/how-to-solve-n-2n-8-for-n?rq=1 – dantopa Apr 03 '17 at 15:17
user63....you're using the wrong inequality – amWhy Apr 03 '17 at 15:24

How do I solve $n <8 \log_2(n)$?

0 Answers0