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Find the general equation of the circle containing $(-4,-2)$ and $(2,0)$, and whose center is contained on the line $5x-2y=19$.

Abelois
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KelDScnd
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1 Answers1

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Hint:

The center of the circle is the common point of the perpendicular bisector line of the segment that has as extremes the two given points, $A=(-4,-2)$ and $B=(2,0)$, and the given straight line : $5x-2y=19$.

Emilio Novati
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  • How should I start solving this problem? – KelDScnd Apr 05 '17 at 20:29
  • Do you know how to find the perpendicular bisector of a segment? If not you can see here: http://math.stackexchange.com/questions/545293/equation-of-a-perpendicular-bisector – Emilio Novati Apr 05 '17 at 20:36
  • (y-y)=m(x-x) is that it? Uhm point-slope intercept form, is the name correct, I can only barely remember it – KelDScnd Apr 05 '17 at 20:39