A tea party is arranged for 16 people along two sides of a long table with 8 chairs each side. four persons wish to sit on one particular and two on other side. in how many ways they all can be seated?
now for four persons can sit on either side. so 2 ways for them, and can be arranged in $P_{4}^{8}$ ways. now other two persons can sit on other side which in $P_{2}^{8}$ ways. for remaining people can be sit in 10! ways. so in all i get answer by multiplying all these. but my textbook misses out factor 2 in answer, rest everything is same. can you tell me where's the problem
thanks