Is this correct, and does it repeat after 2pi?
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This seems to be homework of some kind. What work have you done so far on it? You can get help here, but no one will do your work for you. – Jeff Strom Apr 19 '17 at 06:31
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@JHStrom he already drew a graph – DHMO Apr 19 '17 at 06:35
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2Also, please consider changing your tags. This has nothing to do with differential equations or Laplace transforms. – mickep Apr 19 '17 at 06:35
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@mickep, it is under laplace transform problem in my practice paper. – Heyo Apr 19 '17 at 06:36
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1@Heyo That doesn't mean the problem involves laplace transform. – DHMO Apr 19 '17 at 06:37
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You have drawn the right graph on the interval [0, $\pi $ ] what is your confusion with the other half? – ADA Apr 19 '17 at 06:42
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No, it is not correct. The function you graphed is not $\pi-t$ for $0\leq t\leq 2\pi$.
Update
Now it is correct. And indeed, it repeats (both to the left and the right).
mickep
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the interval is 0≤t<2π, also what am I doing wrong? That is how the graph looks for π-t – Heyo Apr 19 '17 at 06:33
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What you do wrong? You do not graph the function $\pi-t$ on the interval $0\leq t\leq 2\pi$. Do you understand what I mean by that? – mickep Apr 19 '17 at 06:34
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'You do not graph the function for ...' do you mean I am not suppose to draw for that interval or you meant ''You DID not graph the function for ...'' – Heyo Apr 19 '17 at 06:37
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I mean that you did not draw the graph of $\pi-t$ in the interval $0\leq t\leq 2\pi$. – mickep Apr 19 '17 at 06:37
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