Finding the area between curves, calculus, how does my answer look?

Question

i got a test tomorrow and before i step in I wanna make sure i understand this.

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How does my answer look? The prof didnt provide any solutions, just the worksheets, so im worried everything im doing is wrong.

It's good, except that you omitted the limits of evaluation $|^8_2$ for a couple of steps — MPW, Apr 22 '17 at 04:52
Perfect integration. Just don't forget to put the limit of integration — The Dead Legend, Apr 22 '17 at 05:16

score 0 · Answer 1 · answered Apr 22 '17 at 10:33

The limits of integration seems strange, and more other - too.
For $x\in[0,2]\quad \dfrac1{\sqrt{2x}}\ge 0,$ so it should be
$$\int_0^2\frac1{\sqrt{2x}}\,dx = \sqrt2\int_0^2\frac{dx}{2\sqrt{x}} = \sqrt{2}\cdot\sqrt{x}\biggr|_0^2 = 2.$$ But results are the same.

Finding the area between curves, calculus, how does my answer look?

1 Answers1