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An affine combination is like a linear combination, however for coefficients $a_i$:

$$\forall a_i \in F: \sum_{i=0}^{n} a_i = 1$$

However you can also subtract points from each other in affine space, producing a distance vector in the process, but isn't this subtraction just an affine combination with $\sum_{i=0}^{n} a_i = 0$?

hgiesel
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2 Answers2

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Like you say, the coefficients $a_i$ of an affine combination $\sum a_i x_i$ satisfy $\sum a_i = 1$, so with this definition it's a contradiction in terms to speak of an "affine combination with $\sum a_i = 0$". On the other hand, the condition $\sum a_i = 0$ is a linear condition on $n$-tuples of coefficients, so the space of $n$-tuples satisfying this condition is, as mentioned, a vector subspace of $\Bbb F^n$.

Travis Willse
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The distance vector that you get is (generally) not in the affine space.

Lunlun
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