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How does

$$(xy' + x'y)'$$

simplify to

$$(xy + x'y')$$

Edu
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Redjman
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  • @FlybyNight: Since the question is tagged [tag:boolean-algebra] it is probably the Boolean-algebra negation. – hmakholm left over Monica Apr 27 '17 at 16:40
  • Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level. – Fly by Night Apr 27 '17 at 16:41

1 Answers1

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By de Morgan laws : $$(xy'+x'y)'=(x'+y)(x+y')=x'x+x'y'+yx+yy'=xy+x'y'$$ because $xx'=yy'=0$.

(BTW, I suppose $x'$ means $\overline x$, or $\neg x$...)

Nicolas FRANCOIS
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