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I am looking to prove teh following ,

if $ f \in L^1$ then $\lim_{k\to\infty} \int f(x)e^{-|x|^2/k}dx = \int f(x)dx $

I am looking to see if I can use a susbtituion that will make it easy for me to apply LDCT or whether there is a way to apply LDCT directly.

Ángel Mario Gallegos
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Noob101
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1 Answers1

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Note that $|f(x)e^{-|x|^{2}/k}| \leq |f(x)|$ for all $x$ and all $k$. Note that $f$ is integrable by assumption; so $|f|$ is integrable (Try checking the other assumption of LDCT yourself!). Then LDCT gives the desired result.

Yes
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