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How many points may be contained in the intersection of 2 distinct circles?

The answer is 0, 1 and 2 points. I don't get why it could be 0 points when two circles are intersecting.

  • answer: 2. Draw two intersecting circles . – DeepSea May 13 '17 at 04:23
  • @DeepSea: Not necessarily. ... in mathematics the intersection of two things can definitely sometimes be the empty set, so no points in common. – Ted Shifrin May 13 '17 at 04:30
  • 2 distinct circles can intersect in 1 or 2 points – Lê Đức Minh May 13 '17 at 04:30
  • I think the question was too ambiguous, but as Jose answered, concentric circles could be counted for $0$ points. – infinitylord May 13 '17 at 04:38
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    The question is not ambiguous. Take note, it asks: "How many points may be contained in the intersection of $2$ distinct circles?" and NOT "How many points may be contained in the intersection of $2$ distinct intersecting circles?" – Jose Arnaldo Bebita Dris May 13 '17 at 04:46
  • The problem is asking how many different amount of points can fit. If you draw 2 circle intersecting, it has an intersecting point, but it doesn't need to be counted. $0$ points could "fit" in this region. – Eric Lee May 13 '17 at 05:15

2 Answers2

4

No points of intersection

No points of intersection

One point of intersection

One point of intersection

Two points of intersection

Two points of intersection

1

The problem clearly asks:

"How many points may be contained in the intersection of 2 distinct circles?"

And thus, the assumption that the circles are actually intersecting in all three cases is wrong.

  • There can be $0$ points in the intersection of two distinct circles, if they are not intersecting. This implies that there is a distance between any point on circle $A$ and any point on circle $B$.
  • There is $1$ point of intersection, when there is only one point $P$ that is included in both circles.
  • There are $2$ points of intersection, when only two points are common to both circles.

See the image below for clarifications:

enter image description here

Mr. Xcoder
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