It's pretty hard to know what's going on from just this, but assuming that the first table is supposed to mean "find two numbers whose sum is given in the right-hand column" and the second table is supposed to mean "find two numbers whose difference is given in the right-hand column" AND the two tables are expecting the same two values for each row (and this is a lot of assumptions...) you have simple simultaneous equations.
The first row becomes:
$$ a + b = 230 \quad \mbox{and} \quad a - b = 50 $$
for which the solutions are $a=140$ and $b=90$ (add the two equations to get $2a = 280$, solve for $a$ and substitute back into either equation to solve for $b$).
The last row becomes:
$$ a + b = 0.01 \quad \mbox{and} \quad a - b = 0 $$
for which the solutions are $a = 0.005$ and $b=0.005$.
Everything in between you should be able to complete now.