Prove $\sinh(u+v-\eta)\sinh(2v)-\sinh(\eta)\sinh(u-v) = \sinh(2v-\eta)\sinh(u+v)$

Question

How to prove ?

$$\frac{\sinh(u+v-\eta)\sinh(2v)-\sinh(\eta)\sinh(u-v)}{\sinh(u+v)} = \sinh(2v-\eta)$$

Please show what work you have done towards this, and why you are stuck. This will help people give answers at your experience level — lioness99a, Jun 23 '17 at 08:17

score 1 · Accepted Answer · answered Jun 22 '17 at 20:20

1

HINT: use that $$ \sinh z=\frac{e^{z}-e^{-z}}{2} $$

answered Jun 22 '17 at 20:20

Joe

1 Answers1