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We are a group of math enthusiasts and we design and present our mathematical problems to societies. This week I designed this problem and I thought it might be interesting to share it with you here. If you think sharing such problems are not appropriate for this site, then I can remove it. Here is the problem:- A spherical glass is resting on its side on a table. What is the maximum volume of water it can hold in that position? We ignore the thickness of the glass edges. The picture is designed and rendered in $PovRay$. enter image description here

Seyed
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2 Answers2

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Here we need the the volume of a spherical cap: $$V=\frac{\pi h}{6}(3a^2+h^2)$$ where $a$ is the radius of the base of the cap and $h$ is the height of the cap. In order to find $h$ and $a$ we consider Cartesian coordinate system with the $x$-axis along the glass axis and with the origin at the center of the base of the glass. Take the circle of center $(5+4,0)$ and of radius $4$ and the tangent line through $(0,5/2)$. The water level is a line parallel to this tangent which passes through the point $(5+4+\sqrt{4^2-(6/2)^2},6/2)$.

After some unpleasant calculation I found that the maximum volume is around $7.83415\pi$ (not a rational multiple of $\pi$).

Robert Z
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Here is my solution to the maximum volume of water in a glass. The important step in this solution is to find the angle of rotation of the glass when it is resting on the table. enter image description here

Seyed
  • 8,933