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If $|G|=n$ with $n$ square free then there exists at least a normal Sylow subgroup?

Any suggestion are welcome. Thanks.

Juan Carlos Castro
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  • Is free squared = square free = a product of different primes? (no divisible por un cuadrado)? 2) What do you mean by "there exists almost a Sylow..."?
    • – DonAntonio Nov 10 '12 at 00:53
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    See here for example: http://math.stackexchange.com/questions/6078/can-g-of-order-pqr-be-simple-if-its-generated-by-elements-of-orders-p-q/6093#6093 –  Sep 02 '13 at 06:58