Let $S$ be the set of real values of parameter $\lambda$ for which the function $f(x)=2x^3-3(2+\lambda)x^2+12\lambda x$ has exactly one local maxima and exactly one local minima. Then the subset of $S$ is
$(A)(5,\infty)$
$(B)(-4,4)$
$(C)(3,8)$
$(D)(-\infty,-1)$
$$f'(x)=6x^2-6(2+\lambda)x+12\lambda=0$$gives $x=2,\lambda.$
The two local extrema means three roots.So applying the condition of three roots in a cubic polynomial.
$$f(2).f(\lambda)<0$$
gives $\lambda\in(\frac{6}{11},\frac{2}{3})$
But the subsets of $S$ are given $A,C,D$ in the answer.